Torque crank and bucket question

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SUMMARY

The discussion focuses on calculating the minimum force required to raise a 70 kg bucket of water using a crank system with a 0.035 m radius cylinder and a crank handle with a turning radius of 0.35 m. The key equation utilized is torque = F * r * sin, where torque must be balanced between the tension from the bucket and the force applied at the crank. The problem emphasizes the importance of understanding the equilibrium of forces and torques in this mechanical system.

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Homework Statement



A bucket filled with water has a mass of 70 kg and is attached to a rope that is wound around a 0.035 m radius cylinder. A crank with a turning radius of 0.35 m is attached to the end of the cylinder. What minimum force directed perpendicularly to the crank handle is required to raise the bucket?

Homework Equations



obviously torque = F * r * sin

The Attempt at a Solution



my problem here is i cannot accurately understand the diagram (there is no picture that goes along with it). i cannot tell which r value to use. if someone could clarify that i would appreciate it.
 
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This is really an equilibrium problem: the bucket (via the rope) exerts a tension on the cylinder tending to make it turn one way; you (via the crank handle) have to exert a torque in the opposite direction to balance it out.

I was able to dig up a diagram that will help you visualize what's going on. Go to http://www.physics.utah.edu/~woolf/2010_rich/rev4.pdf and look at the diagram that accompanies problem #24.
 

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