Torque on a loop of wire carrying a current

AI Thread Summary
To calculate the maximum torque on a square loop of wire carrying a current, the area of the loop is needed, which can be derived from the wire's length. The wire's total length is 0.477 m, allowing the determination of the side length of the square. The torque formula used is t = NIABsin(θ), where N is the number of turns, I is the current, A is the area, and B is the magnetic field strength. In this case, with one turn (N=1), the calculated torque is 0.023 N*m, indicating a possible error in the area calculation. Accurate area measurement is crucial for correct torque computation.
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A 0.477 m length of wire is formed into a single-turn, square loop in which there is a current of 13.5 A. The loop is placed in a magnetic field of 0.124 T, as shown in the figure below. What is the maximum torque that the loop can experience?

if i had the area i could figure it out
 
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figs said:
if i had the area i could figure it out
But you know it's a square and you have its circumference!
 
A 0.477 m length of wire is formed into a single-turn, square loop



YOu can figure out what is the length of the sides of the square from the given information.
 
how am i to fig out N? t=NIABsin90
 
figs said:
how am i to fig out N? t=NIABsin90
A 0.477 m length of wire is formed into a single-turn
N is the number of turns.
 
that's wut i thought
t=(1)(13.5A)(0.014m2)(0.124)(sin90)
t=0.023 N*m

i did something wrong somewhere
 
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