A uniform door(.81m wide and 2.1m high) weighs 140N and is hung on two hinges that fasten the long left side of the door to a vertical wall. The hinges are 2.1m apart. Assume that the lower hinge bears all the weight of the door. Find the magnitude and direction of the horizontal component of the force applied to the door by a) the upper hinge and the lower hinge. Determine the magnitude and direction of the force applied by the door to b) the upper hinge and the lower hinge.
Fg = 140 N
ƩT = F L
am stuck on how the torque equation applies to this problem
The Attempt at a Solution
i drew the diagram of the door and the hinges spaced 2.01 m apart.
I think you have to make the pivot point/axle point at the bottom hinge
sum of the verticle forces = weight of the door, im assuming this.
Am not sure how to even begin this question. but do i start to make x components at the hinges?
any advice would be helpfull.