Solving Torricelli's Law: Investigating a Bowl with a Hole

AI Thread Summary
The discussion revolves around applying Torricelli's Law to a bowl with a hole, specifically addressing the calculation of drainage time. The user is facing discrepancies between theoretical calculations, which suggest a draining time of 1200 seconds, and experimental results that indicate otherwise. Key equations being utilized include dh/dt*A(h)=-0.6*B*squareroot(2*g*h), with questions raised about the meaning of the function squareroot(1/0.11*h) and the significance of the -0.6 factor. The user seeks clarification on these points and detailed steps to understand the derivation of the 1200 seconds result. Accurate interpretation of the equations and parameters is essential for resolving the issue.
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Homework Statement



ok, I am doing an assignment on torricellis law but I have run into a big problem. I have a bowl which can be described by the function:

squareroot(1/0.11*h). This bowl has a hole in the bottom of a radius of 0.004m. But when I use the relavant formula and integrate it, it says it takes 1200s to drain it. The bowl has a depth of 0.11m. have done experiments and this is far from correct.

Homework Equations



I use the following formula:

dh/dt*A(h)=-0.6*B*squareroot(2*g*h)

where B is the crosssectional area.

I use maple 13 to try to solve it, but it won't give anything reasonable.
 
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What does squareroot(1/0.11*h) represent? Cross-sectional area?

Also, in dh/dt*A(h)=-0.6*B*squareroot(2*g*h), what's the -0.6 for? Show us in detail how you got 1200 s.
 

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