Total Energy a 12V Battery Can Supply

AI Thread Summary
A 12V battery rated at 200 Ah can supply a total energy of 2.4 kWh when calculated using the formula P = IV, where P is power. The initial calculation of energy using E = 1/2 C V^2 resulted in 4,320,000 J, which converts to 1.2 kWh, indicating a misunderstanding of the units involved. The discussion clarified that amp-hours measure charge, not current, and emphasized the need to correctly interpret the formulas for energy and power. Ultimately, the correct approach involves recognizing the relationship between charge, voltage, and energy without misapplying capacitance concepts. The conversation concluded with a resolution of the calculations and understanding of the principles involved.
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Homework Statement


A 12 V battery is rated at 200 Ah (Amps hours). How much total energy can it supply?

Homework Equations


P=IV

The Attempt at a Solution


First I did E = 1/2 C V^2. (Got 4,320,000 J, although I'm not sure if that is correct). But now I need to convert it to kwh so my question is can I use P = IV in this manner:
P = 200 Ah * 12 V
P = 2400 Wh = 2.4 kWh
or do I need to manipulate my original energy finding?

4,320,000 J != 2.4 kWh so one must be wrong
 
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Huh? amp hours? That's a new one.. You plugged in 200 Ah for I..meaning that Ah is a measurement of current? According to Wikipedia, Ah is a measurement of electrical charge..
 
Where did 1/2 C V^2 come from? What did you use for C, and why?

P has units of power, not energy - to get energy you have to multiply by a time, which is what you did, though this might have been accidental since amp-hours are units of charge, not current.

Also, 2400 Wh is not equal to 24 kWh.
 
Alright, using P=IV was the wrong approach

Heres how I calculated Capacitance:
First 200 Ah * 60 min/h * 60 s/min = 720,000 Coulombs.
CV = q
C*12 = 720,000 C
C = 60,000 F (which seems really high)

1/2 * 60,000 F * 12^2 = 4,320,000 J which is equal to 1.2 kWh ( i think )

Am I calculating the correct amount of charge?
 
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CV = q ??
the C refers to capacitance. do you have a capacitor in the circuit?
Hint: what do you have to do to the equation P = IV to get units of energy on the left hand side?
 
Heh, whoops, wasn't thinking about actually needing a capacitor in it.

Anyway, now I got it, thanks all.
 
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