Total Resistance: Solving for 3ohm | Homework Help

foode
Messages
4
Reaction score
0

Homework Statement



Asking me for total resistance



The Attempt at a Solution



I added the one in parallel first which is (1/5 + 1/5)=2.5ohm

Then added 9ohm + 2ohm + 2.5ohm = 13.5ohm( which i think it is the total resistance)
but the right answer should be 3ohm.
 

Attachments

  • un.jpg
    un.jpg
    9.5 KB · Views: 381
Physics news on Phys.org
problem solved
teehee

its 1/9 + 1/4.5 = 4.5/40.5 + 9/40.5 = 13.5/40.5

Therefore 40.5/13.5 = 3ohm
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top