Town clock seconds hand speed and centripetal acceleration

AI Thread Summary
The speed of the tip of the second hand on a town clock can be calculated based on the known speed of the minute hand, which is 0.00136 m/s. To find the centripetal acceleration of the second hand, the relevant equations include the radial acceleration formula, aradial = -v²/r, and the total acceleration equation. The discussion highlights the need for the length of the minute hand to proceed with calculations. Participants express uncertainty about how to begin solving the problem, indicating a need for guidance on applying the equations. Understanding the relationship between the speeds of the clock hands and their lengths is crucial for accurate calculations.
gap0063
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1. (a)The speed of the tip of the minute hand on a
town clock is 0.00136 m/s.
What is the speed of the tip of the second
hand of the same length?
Answer in units of m/s.

(b)What is the centripetal acceleration of the tip
of the second hand?
Answer in units of m/s2.



Homework Equations


atotal = sq rt (a2 radial + a2 tangential) where aradial = −v2/r and atangential = d|v|/dt


The Attempt at a Solution


I have no idea how to start this... I just think I need to use those equations
 
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gap0063 said:

Homework Equations


atotal = sq rt (a2 radial + a2 tangential) where aradial = −v2/r and atangential = d|v|/dt


The Attempt at a Solution


I have no idea how to start this... I just think I need to use those equations
Your relevant equations only deal with acceleration. But anyway, as a place to start, what is the length of the minute hand?
 

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