Trajectory, does it clear a certain height problem help

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The discussion focuses on a physics problem involving a place kicker who must kick a football to clear a crossbar at a height of 3.05 m from a distance of 45.5 m. The ball is kicked with an initial speed of 19.0 m/s at an angle of 48.0°. Initial calculations suggested the ball was 12.23 m underground when it reached the goal, indicating it fell short of the crossbar. However, the final realization was that this distance should include the height of the crossbar, resulting in a total shortfall of 9.18 m. The discussion highlights the importance of correctly interpreting the trajectory calculations in relation to the height requirement.
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Trajectory, "does it clear a certain height" problem help!

Homework Statement


A place kicker must kick a football from a point 45.5 m from the goal, and the ball must clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 19.0 m/s at an angle of 48.0° to the horizontal. By how much does the ball clear or fall short of clearing the crossbar?

Homework Equations


Dy = distance in y = Voy *t -1/2gt^2
Dx = ~~~ x = Vox * t
Vox = initial velocity in x
Voy = ~~~~ y

The Attempt at a Solution


I tried to express Y in terms of x...
since x = Vox * t ... t = x / Vox
then
Dy = Voy(x) / Vox - 4.9 (x^2/Vox^2) assume gravity's 9.8

Plug in 45.5 m for x
Voy = 14.12 m/s
Vox = 12.71 m/s

Dy = -12.23 m

So when the ball is 45.5 m long, its 12.23m underground. which means the ball is 12.23 - 3.05 = 9.18m short of crossing the bar.

Idk... seems simple enough but apprently the answer's wrong.

Thanks a lot for your help!
 
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With a speed of 19.0 m/s at an angle of 48.0° to the horizontal, find the range.
 


Ahhhhhhh i figured it out... since its "underground"... you add the 3.05 meters!
thanks for the helps anyways >.<
 
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