Transforming Trigonometric Functions using Laplace Transformations

kasse
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I'm trying to transform some functions. These two I haven't succeeded transforming:

f(t) = cos((omega)t + tetha)

f(t) = sint*cost

Also, I need help to find the inverse transform of this function:

F(s) = 8 / (s^2 + 4s)
 
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Show us what you tried. It looks to me like you can just take the definition of the laplace transform and integrate by parts twice for the first one.
 
Hey Dick, I have the same question, laplace of cos(t). I did the integration by parts twice and got to the point where I need to take the limit. Now that's where I'm stuck. There is no limit of cosine and sine. They diverge to infinity. Rather they are bounded between 1 and -1. So what do I do?

Here is my solution.

http://i67.photobucket.com/albums/h304/john_ukranian/48maths.jpg

Too large to paste as an image. Its long but very very clearly defined what I did.

Thanks for the help in advance.

Edit: You can go ahead and write on my image to show mistakes. I noticed that I forgot about the 1/s when subtracting the integral from both sides. That should make a difference, but it still doesn't help with the limit as b goes to infinity.

I know I made mistakes, what are they exactly though.
 
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The limits are not a problem sin(t) and cos(t) may oscillate but lim e^(-st) -> 0 at infinity. So evaluated between 0 and infinity sin(t)e^(-st) gives 0 and cos(t)e^(-st) gives -1. And the laplace transform of cos(t) is s/(1+s^2). That's what you are looking for. If A=laplace transform of cos(t), then the integration by parts should lead you to the conclusion A=1/s-A/s^2. Now solve for A.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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