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Transition dipole moment of diatomic molecules

  1. Apr 11, 2015 #1
    Hello Everyone,

    A little question regarding the TDMs between two different electronic states of a diatomic molecule. If I am calculating the TDM from state A to state B, is it the same if we are calculating the TDM from state B to state A? Are these two transitions the same?

    Thank you so much in advance?
  2. jcsd
  3. Apr 12, 2015 #2


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    Science Advisor

    Almost. The dipole moment operator is hermitian. So the TDM from A to B is ##\langle B|d|A \rangle## while the TDM for B to a is ##\langle A |d| B \rangle=(\langle B|d|A \rangle)^*##, i.e. the complex conjugate.
  4. Apr 13, 2015 #3
    Thank you very much DrDu for your help.
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