How Do You Sketch Voltage and Current Waveforms for a Coaxial Transmission Line?

AI Thread Summary
To sketch voltage and current waveforms for a coaxial transmission line with a characteristic impedance of 50 Ω and a load resistance of 16.7 Ω, one must consider the pulse generator's internal resistance of 150 Ω, which affects the reflection coefficient. The outgoing wave's voltage and current can be determined using the relationship I = V/Z0, where Z0 is the characteristic impedance. The returning wave, influenced by the load reflection coefficient, modifies the voltage and current at the source. The interaction between the outgoing and returning waves continues until the input pulse returns to zero volts. Understanding these relationships is crucial for accurately depicting the waveforms over the specified time interval.
tim9000
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Homework Statement



As seen in picture: A coaxial transmission line has a characteristic impedance of 50 Ω, propagation
velocity of 200m/μs, length of 400m, and is terminated by a load resistance, RR =
16.7 Ω. At the sending end the line is connected to a pulse generator that has an
internal resistance of 150 Ω and produces a 40 V, 1 μs long pulse at time, t=0. Sketch
the sending end voltage and current waveforms for 0≤t≤15 µsec.

Homework Equations





The Attempt at a Solution



I'm not sure how to approach this, I'm assuming it has something to do with the inductance and capacitance found from Z = Sqrt(L/C), does anyone have any thoughts?
Thanks
 

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IMO this is a very difficult assignment. It would be so even if the input were an infinite-duration pulse, in which case a lattice diagram could be used. Not sure if this type of diagram could be adapted for a finite-duration pulse (duration < L/v). Should in theory but wouldn't want to try it.

The basic idea of course is that
1. the outgoing wave V and I moves with velocity v, I = V/Z_0;
2. the returning wave V' and I' are related by the load reflection coefficient;
3. the returning wave, added to the ingoing wave, force a new V and I at the source, which will depend on the source impedance;
etc.

This keeps going until the input pulse goes back to zero V.
 
thanks

I see, thanks anyway.
Though what does the internal resistance of the pulse generator have to do with it?
 
tim9000 said:
I see, thanks anyway.
Though what does the internal resistance of the pulse generator have to do with it?

The 150 ohm source resistance determines the fraction of the reflected pulse (back to the source) sent back out again as a new pulse in the +x direction. Us your experssion for the reflection coefficient with Z_0 = 50 ohms and Z_L = 150 ohms.
 
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