Transport theorem, final integral

AI Thread Summary
The discussion revolves around proving the relationship between the time derivative of an integral involving density and a function, specifically showing that the derivative can be expressed in terms of the integral of the function's derivative. The user initially struggles with the rearrangement of derivatives and the dependence of variables in the integral. Clarification is sought regarding the variables and their relationships in the context of a mechanics course. Ultimately, the solution is identified as relying on the definition of the total derivative. This highlights the importance of understanding variable dependencies in integral calculus.
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Homework Statement



Show that

\frac{d}{dt}\int \rho r^{2}\phi dr = \int \rho r^{2}\frac{d\phi}{dr} dr

Homework Equations


Fundamental theorem of calculus

The Attempt at a Solution



So I follow the derivation from the textbook and I think I get the rather sneaky rearrangement of the derivatives, but I do not see how
\int \rho r^{2}\frac{d\phi}{dt} dr = \int \rho r^{2}\left(\frac{\partial \phi}{\partial t}+v\frac{\partial \phi}{\partial r}\right)dr

Note: Integrals are evaluated from a to b, and v(x,t) = dx/dt (e.g. da/dt = v(a,t))
 
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What do the variables depend on? I don't see any problem with the line given a t and r dependence in phi. What subject is this in? Care to share some more problem details?
 
Sorry, I thought it was something standard. It is a mechanics course.

t-time, r - radius, \rho (r,t) is density, \phi (r,t) is an arbitrary differentiable function, a=a(t), b=b(t)

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EDIT:

Nevermind, it is simply using the definition of the total derivative. That's all there is to it...
 
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