Triangle that has the hypo as √(u^2 +1)

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Homework Statement



If I have a triangle that has the hypo as √(u^2 +1)
adj as 1 and oppo as u
I did an integral with trig sub. So I used


Homework Equations



u = tan(θ)

The Attempt at a Solution


At the end of my integral I ended up with an expression (1/4)sin(2θ)
When I substitute back into the integral for theta. I will get (1/2)(u/(sqrt(u^2 +1))
right? How does back sub work if you have 2(theta)
 
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Use ##\sin 2\theta = 2 \sin \theta \cos \theta##. You need the trig functions in terms of ##\theta##, not ##2\theta##.
 
Always like this? With double angle?
 
Could you please use complete sentences? I'm not sure what you're asking.
 
Nevermind thx
 
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