Tricky circuit calculating the total capacitance

AI Thread Summary
The discussion revolves around calculating the equivalent capacitance between points a and b in a complex circuit involving capacitors C1 (4.10 μC) and C2 (1.60 μC). Participants note that the configuration does not fit simple series or parallel rules, prompting the suggestion to use symmetry for a solution. A hint is provided to analyze the circuit by removing an 8 μF capacitor and applying voltage to points a and b to understand the voltage distribution across C1 and C2. The conversation emphasizes the need for a strategic approach rather than straightforward calculations. Understanding the symmetry in the circuit is crucial for solving the problem effectively.
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Homework Statement


Calculate the equivalent capacitance between points a and b in the figure below (C1 = 4.10 μC and C2 = 1.60 μC). Notice that this system is not a simple series or parallel combination.

cw27A8Q.gif


Homework Equations


Series:
CT = [1/c1 + 1/c2...]-1

Parallel:
CT = C1 + C2...

The Attempt at a Solution


I don't know where to tackle this problem...
 
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need_aca_help said:

Homework Statement


Calculate the equivalent capacitance between points a and b in the figure below (C1 = 4.10 μC and C2 = 1.60 μC). Notice that this system is not a simple series or parallel combination.

cw27A8Q.gif


Homework Equations


Series:
CT = [1/c1 + 1/c2...]-1

Parallel:
CT = C1 + C2...

The Attempt at a Solution


I don't know where to tackle this problem...
As the problem states, this is not a combination of series and parallel pieces..

Use symmetry.
 
SammyS said:
As the problem states, this is not a combination of series and parallel pieces..

Use symmetry.

Symmetry...? Not sure how to do that...
 
OK, hint: take out the 8 uF capacitor, apply any voltage to a and b, what is the voltage between the two C1's and what is the voltage between the two C2's?
 

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