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## Homework Statement

x = 5sin(2y +6) find dy in terms of x

## Homework Equations

## The Attempt at a Solution

dx/dy = 8 cos (2y+6)

dy/dx = 1 / (8cos(2y+6)

but according to the mark scheme the final answer is

+ or - 1 / (2 sqrt[16/x^2])

i dont see how on earth they got there :O

Can anyone? Thanks :)