Trig' Identities - Addition Formulae

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[STRIKE]

Homework Statement



Given that cos C = 12/13 where C is a reflex and sin D = 3/5 where D is acute, find the exact value of cos ( C + D ).

Homework Equations





The Attempt at a Solution



I used the Addition Formulae: cos(A+B) = cosAcosB-sinAsinB

cos(12/13)cos(2/5) - sin(1/13)sin(3/5) = 0.999831...

As it says "exact value" I assume my long decimal answer is incorrect. I have inputed it all straight into my calculator. Help me please :smile:[/STRIKE]

Sorry - I've worked out my silly mistake. Thank you for looking :smile:
 
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First off, you're not looking to find

cos(12/13)cos(2/5) - sin(1/13)sin(3/5)

you want to find

cos(C)cos(D) - sin(C)sin(D).

You are given the values of cos(C) and cos(D) in exact for. So your next step is to find the exact values of sin(C) and sin(D). There is one identity that is helpful here, can you think of which one?
 
Thank you for the help JeSuisConf but I've spotted the error.. Silly me, was making it far complicated than it actually is..

Thank you for looking though :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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