Trig' Identities - Addition Formulae

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[STRIKE]

Homework Statement



Given that cos C = 12/13 where C is a reflex and sin D = 3/5 where D is acute, find the exact value of cos ( C + D ).

Homework Equations





The Attempt at a Solution



I used the Addition Formulae: cos(A+B) = cosAcosB-sinAsinB

cos(12/13)cos(2/5) - sin(1/13)sin(3/5) = 0.999831...

As it says "exact value" I assume my long decimal answer is incorrect. I have inputed it all straight into my calculator. Help me please :smile:[/STRIKE]

Sorry - I've worked out my silly mistake. Thank you for looking :smile:
 
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First off, you're not looking to find

cos(12/13)cos(2/5) - sin(1/13)sin(3/5)

you want to find

cos(C)cos(D) - sin(C)sin(D).

You are given the values of cos(C) and cos(D) in exact for. So your next step is to find the exact values of sin(C) and sin(D). There is one identity that is helpful here, can you think of which one?
 
Thank you for the help JeSuisConf but I've spotted the error.. Silly me, was making it far complicated than it actually is..

Thank you for looking though :smile:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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