Confused About Transformation of x: Help Needed!

In summary, the conversation discusses the representation of a signal using complex numbers and equations involving sine and cosine functions. The equations are used to match the initial expression and identify the coefficients A and B, which can be related to polar coordinates.
  • #1
ElDavidas
80
0
Not sure exactly where to post this, but I don't see where this is coming from:

[tex] x = Asin \omega t + Bcos \omega t [/tex]

to

[tex] x = Rsin(\omega t + \phi) [/tex]

where

[tex] R = \sqrt {A^2 + B^2} [/tex] and [tex] cos \phi = A/R [/tex] and [tex] sin \phi = B/R [/tex]

I'd be grateful if someone could point out what is going is on here.
 
Last edited:
Physics news on Phys.org
  • #2
That's close to what you use for representing a signal in the complex plane:

v(t) = A[ cos(wt) + jsin(wt) ]

where you draw a circle of radius A, and horizontal and vertical axes centered on the circle. The horizontal axis is the real axis, and the real Acos(wt) component is projected onto it. The vertical axis is the imaginary component axis, and has the jAsin(wt) component projected onto it.

But your equations are slightly different -- where do they come from?
 
  • #3
Use the addition formula of sin(a+b) on your new sine function.

[tex]\begin{array}{l}
\sin \left( {\alpha + \beta } \right) = \sin \alpha \cos \beta + \sin \beta \cos \alpha \\
R\sin \left( {\omega t + \phi } \right) = R\cos \phi \sin \omega t + R\sin \phi \cos \omega t \\
\end{array}[/tex]

Then identify the coefficients by comparing this to the initial expresseion, to match with A and B.
Notice the similarity with polar coördinates once you set up the equations, if you've seen those.
 

1. What is the concept of "transformation of x"?

The transformation of x is a mathematical process in which a function or equation is modified to create a new function or equation with different properties. It involves changing the variables, coefficients, or constants in the original function to create a new function that behaves differently.

2. Why is understanding the transformation of x important?

Understanding the transformation of x is important because it allows us to manipulate and analyze functions and equations in various ways. This can be useful in solving problems in mathematics, science, and other fields that involve the use of equations.

3. What are the different types of transformations of x?

There are four main types of transformations of x: translation, reflection, dilation, and rotation. Translation involves shifting the graph of a function horizontally or vertically. Reflection involves flipping the graph of a function over a line. Dilation involves stretching or compressing the graph of a function. Rotation involves rotating the graph of a function around a fixed point.

4. How do you perform a transformation of x on a function?

The specific steps for performing a transformation of x on a function will depend on the type of transformation being done. In general, you will need to identify the type of transformation, determine the new values of the variables, coefficients, or constants, and then apply those changes to the original function. It can also be helpful to sketch the graph of the original function and the transformed function to visualize the changes.

5. Can you provide an example of a transformation of x?

One example of a transformation of x is the translation of the function f(x) = x^2 by 3 units to the right. This can be represented by the new function g(x) = (x-3)^2. The x-values in the original function have been decreased by 3, causing the graph to shift 3 units to the right. This transformation can be seen by comparing the graphs of f(x) and g(x).

Similar threads

  • Calculus and Beyond Homework Help
Replies
5
Views
526
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
786
  • Calculus and Beyond Homework Help
Replies
3
Views
562
  • Calculus and Beyond Homework Help
Replies
4
Views
958
  • Calculus and Beyond Homework Help
Replies
6
Views
240
  • Calculus and Beyond Homework Help
Replies
5
Views
972
  • Introductory Physics Homework Help
Replies
4
Views
224
  • Calculus and Beyond Homework Help
Replies
9
Views
962
  • Calculus and Beyond Homework Help
Replies
2
Views
657
Back
Top