Trigonometric equations with sin and cot

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The discussion revolves around solving the equation cot(2sin^(-1)(2/7)). Participants describe their attempts to find the sine and cosine values using the unit circle and the Pythagorean theorem, with one contributor calculating the x value as 4√3 while another claims it should be 3√5. There is uncertainty regarding how to handle the expression involving "2 sin," leading to confusion in obtaining the correct cotangent value. The need for clarity on trigonometric functions and their manipulations is emphasized. Overall, the thread highlights challenges in solving trigonometric equations involving inverse functions.
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Homework Statement


find the value(s): cot(2sin^(-1) 2/7)

The Attempt at a Solution



I solved for sine by drawing a unit circle and the angle. I used the given values of 2 for the y value and 7 for the r value(hypotenuse). By using the pythagorean theorem I found the x value which, for me, came out to 4 sqrt(3). From the x value I was able to find the cosine. Since cotangeant is cosine/ sine I solved for that to get my exact value but it did not come out to the correct answer.
I think it had something to do with the (2 sin) in the equation. I am not sure exactly what to do when an equation gives me a number times sine.
 
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\frac{1}{tan(\frac{2}{sin(2/7)})} ?
 
dbg11 said:

Homework Statement


find the value(s): cot(2sin^(-1) 2/7)

The Attempt at a Solution



I solved for sine by drawing a unit circle and the angle. I used the given values of 2 for the y value and 7 for the r value(hypotenuse). By using the pythagorean theorem I found the x value which, for me, came out to 4 sqrt(3).
I get 3√5, not 4√3.
dbg11 said:
From the x value I was able to find the cosine. Since cotangeant is cosine/ sine I solved for that to get my exact value but it did not come out to the correct answer.
I think it had something to do with the (2 sin) in the equation. I am not sure exactly what to do when an equation gives me a number times sine.
 
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