Trigonometric integral problem

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SUMMARY

The discussion focuses on solving the integral \(\int\frac{1+\sqrt{\cos x}}{\sin x} \, dx\). The user initially breaks down the integral into two parts: \(\int \csc x \, dx\) and \(\int \frac{\sqrt{\cos x}}{\sin x} \, dx\). A suggested substitution of \(\sqrt{\cos x} = a\) simplifies the expression, allowing the use of partial fractions to complete the solution. This method effectively resolves the integral problem presented.

PREREQUISITES
  • Understanding of trigonometric functions and their integrals
  • Familiarity with integral calculus, specifically techniques for integration
  • Knowledge of substitution methods in integration
  • Experience with partial fraction decomposition
NEXT STEPS
  • Study advanced integration techniques, focusing on trigonometric integrals
  • Learn about substitution methods in calculus, particularly for trigonometric functions
  • Explore partial fraction decomposition and its applications in integration
  • Practice solving integrals involving square roots of trigonometric functions
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Students studying calculus, particularly those tackling trigonometric integrals, and educators seeking effective methods for teaching integration techniques.

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Homework Statement


[tex]\int\frac{1+\sqrt{cosx}}{sinx}[/tex] Hi , I really need a help for this


Homework Equations





The Attempt at a Solution



[tex]\int\frac{1+\sqrt{cosx}}{\sqrt{sin}\sqrt{sin}}[/tex]

[tex]\int\frac{1}{sinx}[/tex] + [tex]\int\frac{1}{\sqrt{sinx}}\sqrt{}\frac{cosx}{sinx}[/tex] =

[tex]\int cscx[/tex] + [tex]\int\sqrt{cscx cotx}[/tex] = ?

[tex]\int cscx[/tex] is alright but i have no idea for second part .

do you have any idea ?
 
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Make the substitution [tex]\sqrt{cosx}=a[/tex] Then simplify the resulting expression, use partial fractions and you're done.
 
Yes that's it! thanks for your help...
 

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