1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Trigonometric Integrals problem, more help

  1. Aug 23, 2008 #1
    1. The problem statement, all variables and given/known data

    ∫sec^6 t

    2. Relevant equations
    sec^2 (x)=1+tan^2 (x)


    3. The attempt at a solution
    ∫ (sec^2 (t))^2 * (Sec^2 (t))^2

    ∫(1+tan^2 (x))^2 (1+tan^2 (x))

    ∫(1+2tan^2 (x) +tan^4 (x)) (1+tan^2 (x))
    u=tan (x) du=sec^2 dx

    i'm stuck now
     
  2. jcsd
  3. Aug 23, 2008 #2

    rock.freak667

    User Avatar
    Homework Helper

    Always remeber to put what you integrating with respect to.

    I'll help you out a bit

    [tex]\int sec^6(t) dt= \int sec^4(t)*sec^2(t) dt[/tex]

    Now use sec2=1+tan2 to find what sec4will be.
     
    Last edited by a moderator: Aug 24, 2008
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Trigonometric Integrals problem, more help
Loading...