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Homework Help: Trigonometric Integrals problem, more help

  1. Aug 23, 2008 #1
    1. The problem statement, all variables and given/known data

    ∫sec^6 t

    2. Relevant equations
    sec^2 (x)=1+tan^2 (x)

    3. The attempt at a solution
    ∫ (sec^2 (t))^2 * (Sec^2 (t))^2

    ∫(1+tan^2 (x))^2 (1+tan^2 (x))

    ∫(1+2tan^2 (x) +tan^4 (x)) (1+tan^2 (x))
    u=tan (x) du=sec^2 dx

    i'm stuck now
  2. jcsd
  3. Aug 23, 2008 #2


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    Homework Helper

    Always remeber to put what you integrating with respect to.

    I'll help you out a bit

    [tex]\int sec^6(t) dt= \int sec^4(t)*sec^2(t) dt[/tex]

    Now use sec2=1+tan2 to find what sec4will be.
    Last edited by a moderator: Aug 24, 2008
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