Trigonometry - half angles problems

AI Thread Summary
The discussion focuses on solving trigonometric equations involving half angles and double angles. The user successfully expressed cos(2x) in terms of sin(x) as cos(2x) = 1 - 2sin²(x) but struggles with the equation cos(x) + 3sin(x/2) = 2. They seek guidance on how to eliminate the half angle in their calculations. A suggestion is made to substitute a new variable for the half angle, simplifying the equation to cos(2y) + 3sin(y) = 2. This approach provides clarity on handling half angle problems in trigonometry.
paul18
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Homework Statement


Previous part of the question I have solved:
Express cos(2x) in terms of sin(x):

I got this answer:
cos(2x)=1-2sin2(x)

Hence or otherwise solve the equation
cos(x) + 3sin(x/2) = 2


Homework Equations


Double angle formulae:
cos(2x)=cos(2x) - sin(2x)
sin(2x)=2sin(x)cos(x)


The Attempt at a Solution


So basically I'm doing revision on trig, and I know I've come across this problem before, where you are presented with a full angle and a half angle, but I have failed to find an example. It's something to do with halving a double angle formula I think but I can't even start it. How do I get rid of the half angle? I know I should show an attempt, but I can't even start it off. Just a refresher on how to remove half angles would be great thanks :)
(Yes i have read the rules but this problem is difficult to put into that format properly)
 
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paul18 said:

Homework Statement


Previous part of the question I have solved:
Express cos(2x) in terms of sin(x):

I got this answer:
cos(2x)=1-2sin2(x)

Hence or otherwise solve the equation
cos(x) + 3sin(x/2) = 2


Homework Equations


Double angle formulae:
cos(2x)=cos(2x) - sin(2x)
sin(2x)=2sin(x)cos(x)


The Attempt at a Solution


So basically I'm doing revision on trig, and I know I've come across this problem before, where you are presented with a full angle and a half angle, but I have failed to find an example. It's something to do with halving a double angle formula I think but I can't even start it. How do I get rid of the half angle? I know I should show an attempt, but I can't even start it off. Just a refresher on how to remove half angles would be great thanks :)
(Yes i have read the rules but this problem is difficult to put into that format properly)

If the first part read cos(2z) in terms of sin(z), what would your answer be? Then substitute z for x/2 in the second question
 
paul18 said:

Homework Statement


Previous part of the question I have solved:
Express cos(2x) in terms of sin(x):

I got this answer:
cos(2x)=1-2sin2(x)

Hence or otherwise solve the equation
cos(x) + 3sin(x/2) = 2


Homework Equations


Double angle formulae:
cos(2x)=cos(2x) - sin(2x)
sin(2x)=2sin(x)cos(x)

Note that x = 2 times (x/2). It may be helpful if you substitute another variable, say y, in for x/2. What would x equal? What does this equation:
cos(x) + 3sin(x/2) = 2
look like with the substitutions?
 
eumyang said:
Note that x = 2 times (x/2). It may be helpful if you substitute another variable, say y, in for x/2. What would x equal? What does this equation:
cos(x) + 3sin(x/2) = 2
look like with the substitutions?

cos(2y) + 3sin(y) = 2.
Thanks very much that's what I needed a refresher on :)
 
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