Trigonometry Identity problem I been trying to solve all day

AI Thread Summary
The discussion revolves around solving the trigonometric equation 3cos(x) + 3 = 2sin^2(x) for 0 <= x < 2pi. Participants suggest rewriting the equation in standard form, leading to 2cos^2(x) + 3cos(x) + 1 = 0, which simplifies the solving process. One user initially struggles with the distribution and movement of terms but eventually recognizes the need to factor the equation properly. The importance of double-checking work and understanding the relationship between factored forms and expanded forms is emphasized. Overall, the conversation highlights common challenges in solving trigonometric identities and the value of collaborative problem-solving.
Juliano
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Homework Statement


solve 3cos(x) + 3 = 2 sin^2(x) where 0 <= x < 2pi

Homework Equations


The Attempt at a Solution


3(cos(x) + 1) = 2 sin^2(x)
3(cos(x) + 1) = 2 (1- cos^2(x))
I've tried this variation, and a couple others but it just does not pan out. Please help.

Oh yeah we have a real uninformative book.
 
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Juliano said:
3(cos(x) + 1) = 2 sin^2(x)
3(cos(x) + 1) = 2 (1- cos^2(x))
I've tried this variation, and a couple others but it just does not pan out. Please help.

Oh yeah we have a real uninformative book.
Don't factor out the 3 on the left side. Instead, distribute the right side, and move everything to the left side. After doing that, do you recognize the equation?


01
 
OK so I get the following
3 cos(x) + 3 = 2 - 2 cos^2(x)
3 cos(x) + 1 + 2 cos^2(x)=0
I tried this variation before, but I was unsure of what to do with the 1+2 cos^2(x) part. or maybe I'm just doing something wrong with the distribution and movement of the right side.
 
hold on I think I understand now.
(3 cos(x)+1)(2cos^2(x))= 0, the solve those two for 0
 
No no no, that's not right. It's best if you put the equation in "standard form" first, like this:
2cos^2(x) + 3 cos(x) + 1 = 0
Do you see what to do now?


01
 
wow. My head was so wrapped up in Identities I didn't even think to factor them in standard form
(cos +1)(2cos+1)=0
Thank you for shining a light through this fogged up brain of mine
 
Juliano said:
hold on I think I understand now.
(3 cos(x)+1)(2cos^2(x))= 0, the solve those two for 0
Althought the correct approach has already been pointed out, the equation above deserves a further comment. You can't get to the equation above from the one you showed in a previous post:
3 cos(x) + 1 + 2 cos^2(x)=0
If you multiply out your factored form, you get only two terms, not the three shown just above.
 
Yeah I see what you mean Mark44, Teachers always tell you to double check doing what you just did. Maybe I need to start doing that more.
 
Yeah, maybe you should, especially when you're in the early stages of learning something.
 
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