The discussion centers on calculating the length of the vector a = 1/sqrt(29) * (-2*sint, 0, -2*cost). The correct length is determined to be [2*sqrt(2)]/sqrt(29}, which arises from the expression sqrt{[(-2*sint)/sqrt(29)]^2 + [(-2*cost)/sqrt(29)]^2}. The initial miscalculation of 2/sqrt(29) was clarified through the application of the Pythagorean identity, leading to the conclusion that the correct evaluation involves recognizing that 4sin^2(t) + 4cos^2(t) equals 4, not 8.
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No need to. You answer is correct. 2\sqrt{2}/\sqrt{29} would be \sqrt{4+ 4}/\sqrt{29} but 4sin^2(t)+ 4cos^2(t)= 4 not 4+ 4.hanelliot said:Homework Statement
a = 1/sqrt(29) * (-2*sint, 0, -2*cost)
length of a is?
Homework Equations
The Attempt at a Solution
ignoring 0, we have sqrt{[(-2*sint)/sqrt(29)]^2 + [(-2*cost)/sqrt(29)]^2}. I get 2/sqrt(29) but answer is [2*sqrt(2)]/sqrt(29). Can anyone do this step by step and show me please..