What is the value of secx when sinx = -0.40 and tanx > 0?

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When sinx = -0.40 and tanx > 0, secx can be determined using the relationship between sine, cosine, and secant. The discussion indicates that the angle corresponding to sin(x) = -0.40 is in the fourth quadrant, while the second angle is in the third quadrant. To find secx, the cosine value must be calculated, as secx is the reciprocal of cosine. The correct value of secx, rounded to the nearest hundredth, is determined to be 1.09. This conclusion is reached by considering the properties of trigonometric functions in different quadrants.
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If sinx = -0.40 and tanx > 0, then secx, to the nearest hundreth, is

A) 0.92

B) -0.92

C) -1.09

D) 1.09

So I figured that sin^-1 = -23.57817848, but I don't know how to get sec, can someone help!
 
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I would assume it is in the 3rd quadrant as well
 
There are 2 angles for x that correspond to sin(x) = -0.40
the one you found is in the 4th quadrant, there is one in the 3rd quadrant as well
 
Thanks, Ill try solving it now
 

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