Triple Integral of z over [0, 2*pi] for r [1, 2]

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[SOLVED] Triple integral

Homework Statement



Calculate the triple integral of z when z [(r-1), sqrt(1-(r-2)^2)], r [1, 2], tetha [0, 2*pi]

2. The attempt at a solution

I've tried again and again, and I always get (17/4)*pi, while the answer is pi/2. Is there anything wrong with antiderivating in this order: dz, dr, d(tetha)?
 
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Thread 'Finding the nth roots of a complex number'

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