Tuna or a Kingfish probability

  • Thread starter Thread starter danago
  • Start date Start date
  • Tags Tags
    Probability
AI Thread Summary
The discussion centers on determining whether a fish weighing 22kg is more likely to be a Tuna or a Kingfish based on their respective weight distributions. The Tuna has a mean weight of 22kg with a standard deviation of 3kg, while the Kingfish has a mean of 20kg and a standard deviation of 4kg. Given that the Tuna's mean aligns exactly with the caught weight, it suggests a higher probability of the fish being a Tuna. Additionally, the concept of maximum likelihood estimation supports this conclusion, indicating that the 22kg weight is more probable under the Tuna's distribution. Ultimately, the analysis concludes that the fish is more likely to be a Tuna.
danago
Gold Member
Messages
1,118
Reaction score
4
A statistician went fishing, and noticed that the masses of the fish he caught could be modeled with a normal distribution. He noticed that the Tuna had a mean mass of 22kg, with a standard deviation of 3kg. The Kingfish had a mean of 20kg, and standard deviation of 4kg.

A fish of 22kg is caught; which fish is it more likely to be--A Tuna or a Kingfish?


Well, upon reading the question, i automatically thought the Tuna, since the tuna, on average, are 22kg, and the standard deviation is 3kg, so they are generally closer to their mean than the Kingfish. Is the question really that simple, or should i be looking deeper into it?
 
Physics news on Phys.org
well the thing is that it can be both. both have a probability that it is 22kg. but if you ask me, i'll say it is the tuna. and if the question is about probability, then is is a 1 in 2 chances for both fishes.
(visit my blog!)
 
Actually, I would think this is a "conditional probability" problem and you would have to know the relative numbers of fish in the area! However, since that information is not given, it looks more like an "estimation of parameters' problem: Given the mean weight of a sample of fish, estimate the true mean weight. The simplest is the maximum likelyhood estimate: which true mean weight gives the highest probability of getting that sample?
Here, the sample is just one fish but obviously, if the true mean weight were 22kg that would make the probability of catching a fish of that weight higher than if you used 20kg as mean weight. Since the "maximum likelyhood estimate" is 22 kg the fish caught is more likely to be a tuna than a kingfish- the obvious answer anyway.
 
Alright thanks for the help guys :smile:
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top