Two blocks - one on a table and one hanging - acceleration with friction

  • Thread starter Hemmelig
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  • #26
Hootenanny
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Hmm, so what do i do next ?

I don't know T and i don't know a
Hmmm, you have a system of simultaneous equations, two equations with two unknowns. Solve.
 
  • #27
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Ah, ofcourse

From equation a i have that T=12,753 - 1,3a

From equation b i have that T=2,25a + 9,93

I solve for T and get a=2,823/3,55 = 0,7952

I then put it into equation a and get t=11,71

I can then use V^2 = V0^2 + 2a (x-x0) to find the speed after 0.03m (is that the best equation to use ? )

I get v=0,2184307076

Thank you so much for your help
 
  • #28
Hootenanny
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I can then use V^2 = V0^2 + 2a (x-x0) to find the speed after 0.03m (is that the best equation to use ? )
Yup, that's the one that I would use :approve:
Thank you so much for your help
A pleasure :smile:.

As an aside, this method is applicable to any pulley question.
  1. Identify the forces acting on each individual body.
  2. Plug the results of (1) into Newton's Second Law, again for each individual body.
  3. You know that if the string is light and inextensible the tension and acceleration must be the same for each body.
  4. Solve for a and T.
 
Last edited:
  • #29
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Great :)

Again, thank you so much
 

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