Two coplanar lines and finding the equation

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Two coplanar lines, a and b, are perpendicular, with line a passing through points (3,2,3) and (8,10,6). The user seeks to find the equation for line b, which passes through point (7,49,25). They initially used the cross product to determine a direction vector but are unsure how to proceed with the second direction vector or utilize the given point for line b. Clarification on the concept of coplanarity and direction vectors is also requested, indicating confusion about the relationships between the points and vectors involved. The discussion emphasizes the need for guidance on establishing the equations for the lines based on the provided coordinates.
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Homework Statement


Two coplanar lines, a and b are perpendicular to each other. a passes through the points (3,2,3) and (8,10,6). Find the equation for b if it passes through the point (7,49,25).

Homework Equations


The equation were trying to find is r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2]

The Attempt at a Solution


Basically since the coordinates are perpendicular I used the cross product to find one direction vector. For my position vector I used (3,2,3). Now I'm not sure what to do with the last point (7,49,25) or what to do to find my second direction vector. I'm not even sure if I did the first part right. Help would be appreciated thanks!

EDIT: I originally posted this in a different section but somebody told me it'd be better if I post it here. So if a mod could remove the other thread in the physics section that'd be awesome.
 
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welcome to pf!

hi gundamshadow! welcome to pf! :smile:

have you drawn this?

you have three known points, B C and D, and you want the line through B perpendicular to CD :wink:
 
Thank you for the welcome :)

So I'm assuming B is (3,2,3) and C is (8,10,6) etc.
In that case how would I go about finding direction vectors if they're perpendicular? Is it a combination of cross product of B and C?

EDIT: Also the term coplanar, does that mean the vectors in the equation have to be a multiple?
 
come on! :rolleyes:

it's a simple triangle question! :smile:

(you can use parallel lines, and cross products :wink:)

(coplanar means in the same plane … any vector in it will be a linear sum of any two distinct vectors in it)
 
I`m sorry I am really lost now. I subtracted (3,2,3) and (8,10,6) and got (5,8,3). So that is my position vector I hope.

So as it stands the equation is r= (5,8,3) + s (xyz) + t (xyz)

How do I get the other coordinates for vector s and t
 
hi gundamshadow! :smile:
gundamshadow said:
I subtracted (3,2,3) and (8,10,6) and got (5,8,3).

yes, that's the direction of your line CD

so what is the line through B parallel to that?
 
tiny-tim said:
hi gundamshadow! :smile:


yes, that's the direction of your line CD

so what is the line through B parallel to that?

I thought that was the position vectorÉ And if its parallel does that mean that CD dot product by (7,49,25) will be zeroÉ
 
gundamshadow said:
I thought that was the position vectorÉ And if its parallel does that mean that CD dot product by (7,49,25) will be zeroÉ

you've lost me :confused:

what is the line through B parallel to CD?
 
Im kinda lost too. And I got (0,-3,8)
 
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EDIT: Realised bumping not allowed. Please delete post. Sorry!
 
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