Two identical droplets of water.... [Potential]

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Two identical water droplets, each with a charge of 7.92 pC and a surface potential of 144 Volts, are merged into one larger droplet. The discussion highlights that while charge is conserved, the potential cannot simply be added together due to the change in radius and shape of the new droplet. The potential of the combined droplet must be calculated using the formula V = kq/r, taking into account the new radius and total charge. The conversation emphasizes that the problem is not straightforward and requires an understanding of how merging affects potential. Ultimately, the potential of the new droplet must be determined through proper calculations rather than simple addition.
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Homework Statement


Suppose you have two identical droplets of water, each carrying charge 7.92 pC spread uniformly through their volume. The potential on the surface of each is 144 Volts.

Now, you merge the two drops, forming one spherical droplet of water. If no charge is lost, find the potential at the surface of this new large water droplet. in V.

Homework Equations


I don't have any equations since it's "water droplet" with no specified shape.

General formula for potential due to a single point charge is V = kq/r

The Attempt at a Solution


Is this question easy or tricky? Shouldn't the answer be 144 + 144 = 288 V? Due to conservation of charges?
 
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Antonius said:
I don't have any equations since it's "water droplet" with no specified shape.
Which shape do you expect for a droplet without contact to anything else?
What is the potential from such an object?
Antonius said:
Is this question easy or tricky?
It is not tricky, but it is not as easy as adding two numbers.
Antonius said:
Due to conservation of charges?
Charge is conserved, but that does not mean you can just add potentials.
 
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The new droplet of water has what radius, assuming sphericity? What total charge? Ergo, what potential?
 
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