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## Homework Statement

Two masses attached to opposite ends of a spring. What is the Force felt by each mass if each mass is stretched by Xmeters in opposite directions away from each other.

## Homework Equations

F=-kx

## The Attempt at a Solution

So my book says the answer is F=k*2x.

Each mass has the same mass and is stretched from their equilibrium by the same amount X. so the spring is stretched a total amount of 2x.

So since the spring force is proportional to the displacement of the spring/stretch of the spring, it would make sense that the spring force would be F=k*2x since 2x is the total displacement.

But what I'm havin gtrouble understanding is how to distinguish between situations like this when the spring is stretched by the same amount on both sides and problems where the same

**force**is applied to both sides.

When the same force is applied to both sides, you use the same formula Fspring = kx , but for the force applied you only consider one of the applied forces rather than both combined, on the notion that the other side is whats keeping the spring from accelerating, newtons third law.

But when you actaully compress the spring or stretch it by a certain amount, even if you stretch it from both ends, you consider the total stretch added from both ends to consider the recoil force, am i right?

And lastly, (Thanks guys haha) is the reason why you dont consider both forces when you apply the same force to both sides that compression could only occur if there was a counter force? Because the lack of movement

**allows**for the compression to occur? Does that make sense? its wierd because it's like we're using the applied force twice,

once to cancel out the counter force from the other end of the spring (i.e. from a wall or from someone on the other end of the spring)and then

**again**

*when determining the compression caused by said force.*