Two particles and magnetic field

AI Thread Summary
Two charged particles, A and B, enter a magnetic field at right angles with the same velocity. Particle A has charge q and mass m, while particle B has charge -q and mass 2m. Both particles experience the same force magnitude due to their equal charge, but they circulate in opposite directions because of their differing masses. As a result, particle A has a gyroradius that is half that of particle B. The discussion concludes that the differences in their motion stem from their mass and acceleration under the same force.
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Homework Statement


Two particles, 'A' with charge and mass of q and m and 'B' with charge and mass of -q and 2m, each enter at right angles to a uniform magnetic field with the same velocity. Compare the circular paths that each begin upon entering the magnetic field.

A) A experiences the same force magnitude as that of B and circulates in the same direction as B with A's radius equal to that of B.
B) B experiences twice force magnitude as that of A and circulates in the opposite direction as A with A's radius at half that of B.
C) B experiences twice force magnitude as that of A and circulates in the opposite direction as A with A's radius equal to that of B.
D) A experiences the same force magnitude as that of B and circulates in the opposite direction as B with A's radius at half that of B.

Homework Equations


Bvq=mv^2/r

The Attempt at a Solution


Since the magnetic field is uniform, B can be disregarded. So can v since it is the same velocity for both particles. So the equation can be reduced to q=m/r, and to rearrange and solve for r, r=m/q. Then I plugged in m and q for both particles and I get A=m/q and B=-2m/q. So B circulates the in opposite direction as A, and A has half the radius as B, so that narrows it down to B and D. I'm a little stuck on the force. Does B experience twice the force magnitude as A because B=2m while A=m?
 
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The gyroradius equation comes straight from the Lorentz force law,

\vec{F} = q \vec{v}\times\vec{B}.

So, what can you conclude about the relative forces?
 
Steely Dan said:
The gyroradius equation comes straight from the Lorentz force law,

\vec{F} = q \vec{v}\times\vec{B}.

So, what can you conclude about the relative forces?

They both have the same force magnitude because they both have q for the charge.
 
kimberlyann9 said:
They both have the same force magnitude because they both have q for the charge.

Exactly. They simply have different motions because they have different masses, and therefore different accelerations when subjected to the same force.
 
Steely Dan said:
Exactly. They simply have different motions because they have different masses, and therefore different accelerations when subjected to the same force.

Thanks!
 
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