Two particles and magnetic field

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Homework Help Overview

The problem involves two charged particles, 'A' and 'B', entering a uniform magnetic field at right angles with the same velocity. The task is to compare their circular paths based on their charges and masses.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to simplify the problem by reducing the equation to a relationship between mass and charge, leading to a comparison of the radii of the circular paths. Questions arise regarding the force experienced by each particle and how it relates to their respective masses.

Discussion Status

Participants are exploring the implications of the Lorentz force law and its relation to the forces acting on the particles. Some guidance has been offered regarding the equality of force magnitudes due to the charge, while others discuss the effects of differing masses on motion and acceleration.

Contextual Notes

There is an ongoing discussion about the assumptions made regarding the uniform magnetic field and the implications of the charges and masses of the particles on their motion.

kimberlyann9
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Homework Statement


Two particles, 'A' with charge and mass of q and m and 'B' with charge and mass of -q and 2m, each enter at right angles to a uniform magnetic field with the same velocity. Compare the circular paths that each begin upon entering the magnetic field.

A) A experiences the same force magnitude as that of B and circulates in the same direction as B with A's radius equal to that of B.
B) B experiences twice force magnitude as that of A and circulates in the opposite direction as A with A's radius at half that of B.
C) B experiences twice force magnitude as that of A and circulates in the opposite direction as A with A's radius equal to that of B.
D) A experiences the same force magnitude as that of B and circulates in the opposite direction as B with A's radius at half that of B.

Homework Equations


Bvq=mv^2/r

The Attempt at a Solution


Since the magnetic field is uniform, B can be disregarded. So can v since it is the same velocity for both particles. So the equation can be reduced to q=m/r, and to rearrange and solve for r, r=m/q. Then I plugged in m and q for both particles and I get A=m/q and B=-2m/q. So B circulates the in opposite direction as A, and A has half the radius as B, so that narrows it down to B and D. I'm a little stuck on the force. Does B experience twice the force magnitude as A because B=2m while A=m?
 
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The gyroradius equation comes straight from the Lorentz force law,

[tex]\vec{F} = q \vec{v}\times\vec{B}.[/tex]

So, what can you conclude about the relative forces?
 
Steely Dan said:
The gyroradius equation comes straight from the Lorentz force law,

[tex]\vec{F} = q \vec{v}\times\vec{B}.[/tex]

So, what can you conclude about the relative forces?

They both have the same force magnitude because they both have q for the charge.
 
kimberlyann9 said:
They both have the same force magnitude because they both have q for the charge.

Exactly. They simply have different motions because they have different masses, and therefore different accelerations when subjected to the same force.
 
Steely Dan said:
Exactly. They simply have different motions because they have different masses, and therefore different accelerations when subjected to the same force.

Thanks!
 

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