Two pipes of water flowing into one another

  • Thread starter Thread starter Idea04
  • Start date Start date
  • Tags Tags
    Pipes Water
AI Thread Summary
When two pipes of water at 5psi flow into a tee, the interaction does not increase the total pressure at the outlet. Instead, the outlet pressure will be lower than the inlet pressure due to the nature of fluid dynamics, where liquids flow down the pressure gradient. The combined forces of the water do not amplify the pressure; rather, they maintain the pressure differential necessary for flow. The outlet will experience a decrease in pressure relative to the inlets. Understanding these principles is crucial for effective fluid system design.
Idea04
Messages
194
Reaction score
1
If you have two pipes of water flowing directly into one another and both are at 5psi and at the point where they interact with each other there is a tube like a tee. where the fluid can escape. Will the two force of water increase the total pressure and the force of the water leaving the tee.
 
Physics news on Phys.org
If one has two inlets and one outlet, the outlet pressure must be less than the inlet pressure. Liquids flow down the pressure gradient.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top