Uncertainty Principle and dart of mass

teme92
Messages
185
Reaction score
2

Homework Statement


A dart of mass ##m## is dropped from a height ##l##. Formulate the uncertainty principle and estimate the minimum limitations, set by the uncertainty principle, of the accuracy that can be achieved in the lateral ##x## position after falling, given an original uncertainty ##\Delta x##, and no original uncertainty in y.

Homework Equations

The Attempt at a Solution


The time to drop is ##\sqrt{2l/g}##. With uncertainty the dart hits the ground at a distance ##R## where:

##R=\Delta x+\sqrt{2l/g}\space \Delta p/m \geq\Delta x +\sqrt{2l/g}\space \hbar/2m\Delta x##

This next part I found from a book but I don't understand how its got from above:

##\Delta x=(l\hbar^2/2m^2g)^{\frac{1}{4}}##

with ##R\geq(8l\hbar^2/m^2g)^{\frac{1}{4}}##

Could anyone clarify how ##\Delta x## and ##R## were found?
 
Last edited:
Physics news on Phys.org
Please review the statement of the problem, it seems that the last sentence is not finished and maybe we miss important data.
 
Hey soarce I edited the omission.
 
Your derivation seems correct. Can you give us the reference from where you took the formula for ##\Delta x##?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top