Uncertainty principle, relating the uncertainty in position to the uncertainty

[ttiger654]

Prove the uncertainty principle, relating the uncertainty in position (A=x) to the uncertainty in energy (B=p^2/(2m + V)):

\sigma x\sigma H \geq \hbar/2m |<P>|

For stationary states this doesn't tell you much -- why not??

 

[StatMechGuy]

What have you done so far? Do you know the generalized uncertainty relation? Read the guidelines to this forum, please, and we'll be able to help more.

 

[luck.rajesh]

Prove the uncertainty principle, relating the uncertainty in position (A=x) to the uncertainty in energy (B=p^2/(2m + V)):

\sigma x\sigma H \geq \hbar/2m |<P>|

For stationary states this doesn't tell you much -- why not??

solution-
[x,p2/2m+V]=1/2m[x, p2]+[x,V];

[x, p2]= xp2 − p2x = xp2 − pxp + pxp − p2x = [x, p]p + p[x, p].

using the equation [x,p]=ih{this is known as canonocal commutation relation}

[x, p2]= i
hp + pi
h = 2i
hp. and And [x, V ] = 0,
so [x,p2/2m+ V]=1/2m(2ih
p) = i
hp/m

The generalized uncertainty principle says, in this case,

σ2xσ2H≥{(1/2i
)(ih/m)
<p>}^2={h/2m<
p>}^2⇒ σxσH ≥h/2m|<
p>|. QED

For stationary states σH = 0 and
p = 0, so it just says 0 ≥ 0.

 

[luck.rajesh]

for reference u can use {griffiths_d.j._introduction_to_quantum_mechanics__2ed.}