From "Martin & Shaw", regarding problem 3.5 (sometimes it uses natural units "c=1"):(adsbygoogle = window.adsbygoogle || []).push({});

"The particle has [itex]\gamma = E/m \approx 10[/itex], hence [itex]\tau \approx c[/itex] (?) and the average distance is [itex]d \approx c \gamma \tau \approx 3 \times 10^{-14}m[/itex] if we assume a lifetime for the particle at rest of [itex]10^{-23}[/itex]."

I don't understand why [itex]\tau \approx c[/itex].

Since [itex]v = c \sqrt{1 - \frac{1}{\gamma^2}}, v = 0.994 c[/itex] and I would agree that [itex]v \approx c[/itex], not [itex]\tau[/itex].

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# Unclear approximation in relativistic calculation of particle's distance travelled

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