Understand Decreasing Function: Limit g'(x) at Infinity

Sethka
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Now what should I look up to understand a question like this one:

Function h is decreasing on the interval [4,infinity) and lim h(x)(with x approaching infinity)=8, what would be the limit g'(x)(with x approaching infinity)?

I don't nessicarily need the answer, but could someone point me in the right direction?
 
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Earlier you asked about a function g that was simply decreasing and were told that you cannot say anything about the derivative as x went to infinity except that it would be non-negative (the limit could be 0).

Is this a revision of that problem? If so, it is a good revision. (I won't make any remark about not being able to find g' from information about h!) The difference now is that h goes to a constant as x goes to infinity- that's more important than "decreasing". Given any \epsilon> 0, there must exist a "neighborhood of infinity" (interval (a, \infty)) on which h(x) differs less than \epsilon from 8. What does that tell you about the derivative of h?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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