Understanding Conservation of Momentum and Energy in Ideal Quantum Experiments

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In the discussion of the ideal quantum experiment and Compton scattering, my book (Shankar page 23) gives these equations for the conservation of momentum and energy:

cp' = cp +h-bar(\omega+\omega')
E' = E +h-bar(\omega-\omega')


This experiment involved a photon of known energy and momentum colliding with a particle of unknown energy and momentum.

c is the speed of light, h-bar is h/(2*pi) omega is the frequency of the photon, E is energy, and p is momentum

Can someone please explain how those equations represent the conservation of momentum and energy?
 
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Put glasses on your nose if you need: this is what is written.

Regards, Dany.
 
Why is it \omega - \omega' for energy and \omega + \omega' for momentum?
 
I see the photon is moving at first and right-moving after the collision and p and p' are only the modulus of the momentum.
 
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