Understanding Continuity in the Cross Product Function

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1. Show that the cross product is a continuous function.

The Attempt at a Solution



I have tried to apply the definition of continuity: find a delta such that
|x-y|< delta implies |f(x)-f(y)|< epsilon
but I'm having trouble making sense of what |x-y| is.
As I see it, x is a pairs of vectors in R^3 and so is y. Then what is |x-y|? and how do I get to the conclusion?
 
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There is a vector that connects x with y, so the norm of this vector would be the distance between x and y.
 
I am saying that just x is a pair of vectors in R^3. The cross product function takes that pair of vectors and gives you one vector (that is perpendicular to the original two).
So x is 2 vectors and y is another 2 vectors. What would |x-y| be?

Or is my understanding wrong? In that case, how can I approach the problem?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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