Understanding cot2(theta) = A-C / B

  • Thread starter Thread starter Terrell
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around the transformation of an equation involving variables \(x'\) and \(y'\) into a new form that includes a coefficient \(B'\) related to trigonometric functions. Participants are exploring the relationship between the original equation and the new expression for \(B'\).

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the process of expanding the original equation and collecting terms based on powers of \(x'\) and \(y'\). There are questions about the nature of the transformation from the original equation to the new definition of \(B'\) and how to deduce it step by step.

Discussion Status

Some participants have provided insights into the nature of the transformation, suggesting that \(B'\) is simply a new symbol for the coefficient of \(x'y'\). Others express uncertainty about how to begin the deduction process, indicating a lack of consensus on the steps involved.

Contextual Notes

Participants note that the original equation is not an assignment but part of self-study. There is also mention of the author’s freedom to define new symbols, which raises questions about the clarity of definitions used in the derivation.

Terrell
Messages
316
Reaction score
26

Homework Statement


How did it go from A'x'^2 + B'x'y' + C'y'^2 + D'x' +E'y' + F = 0 to become B' = 2(C-A)sin(theta)cos(theta) + B(cos^2(theta) - sin^2(theta))?

*this is not an assignment, I am just self studying :P
 

Attachments

  • cot2theta2.png
    cot2theta2.png
    60.6 KB · Views: 1,245
Last edited:
Physics news on Phys.org
Expand the top most equation then collect the terms based on the powers of ##x'## and ##y'##. To obtain (12), just keep track on the terms in the top most equation which contain ##x'y'##.
 
Terrell said:

Homework Statement


How did it go from A'x'^2 + Bx'y' + C'y'^2 + D'x' +E'y' + F = 0 to become B' = 2(C-A)sin(theta)cos(theta) + B(cos^2(theta) - sin^2(theta))?
The latter is not a deduction from the former. It is simply a definition, which the author is free to make, as the symbol B' has not been used up to that point.

The deduction is the equation immediately after the 'where...' part.
 
blue_leaf77 said:
Expand the top most equation then collect the terms based on the powers of ##x'## and ##y'##. To obtain (12), just keep track on the terms in the top most equation which contain ##x'y'##.
yes. i got that part, but how do i get from the 2nd equation to the third equation?
 
andrewkirk said:
The latter is not a deduction from the former. It is simply a definition, which the author is free to make, as the symbol B' has not been used up to that point.

The deduction is the equation immediately after the 'where...' part.
but how do i deduce it? what is step1? i don't know how to start.. from A'x'^2 + B'x'y' + ... + F = 0 to B' = 2(C - A)...
 
Like andrew has said, ##B'## is just a symbol used to represent the coefficient of ##x'y'##. The author could have retained the original form of the coefficient in terms of ##A##, ##B##, ##C##, and ##\theta##, but it will require more space. He chose ##B'## as the new coefficient for ##x'y'## because this symbol has not been used in the previous derivation.
 
i got it! just keep track and combine all the terms with x'y' then equate to zero and simplify. thanks guys!
 
can I get the name of the book?
 
mkeaudric said:
can I get the name of the book?
This thread is six years old. Don't count on a response from the participants.
 
  • Like
Likes   Reactions: Mark44

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
Replies
2
Views
3K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
2K
Replies
56
Views
6K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K