Understanding Electric Force: Calculating Change in Potential Energy

AI Thread Summary
The discussion revolves around calculating the change in potential energy when a charge +q is moved from a distance of 3r to 2r by a charge -q. The initial calculations involve using the work-energy principle and the formula for electric potential energy, resulting in an expression for deltaU. However, confusion arises regarding the interpretation of the potential energy formula and the correct application of the distance in the context of the problem. The participant realizes the mistake in their understanding but indicates that they have encountered another problem related to the topic. The discussion highlights the complexities of electric force and potential energy calculations in electrostatics.
soljaragz
Messages
15
Reaction score
0
Here is the question that I have no idea what is happening

"What is the change in potential energy of a particle of charge +q that is brougt from a distance of 3r to a distance of 2r by a particle of charge -q? "

Here's what I tried

-W = deltaU
W = qEd
W = (kq1q2/r^2) d
d= 3r - 2r = r

substituting I get
W = kq1q2/r
so deltaU = -kq1q2/r.....im correct up to here, but its not the final answer according to the book,...the explanation then shows some weird things that I don't understand.

but isn't the question asking for change in potential
so shouldn't deltaU (-kq1q2/r) be the answer?
 
Last edited:
Physics news on Phys.org
Hint: The potential energy of two charges separated by a distance r is given by kq1q2/r (where the zero level is taken to be at r = infinity).
 
[nvm i get it now]
I have another problem though
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top