Understanding Electric Potential and Field in a Ring of Charge

AI Thread Summary
The discussion focuses on the relationship between electric potential and electric field along the Z axis of a ring of charge. It confirms that the electric field, E_z, is indeed equal to the negative gradient of the potential, leading to the equation E_z = -∂_z V. The potential V can be calculated using V = -∫ dz E_z, with the constant of integration being arbitrary. While it's common to set the potential to zero at infinity, this is not a strict requirement. The conversation clarifies these concepts in the context of electrostatics.
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Homework Statement


A potentially silly question that I have put off too long to ask, any assistance is greatly appreciated!

The electric field evaluated along the Z axis of a ring of charge centered on the origin and lying on the XY plane is only a function of ##z## and points only along ##z##. Since
$$\vec{E} = - \nabla V = - \big( \partial _x V \hat{x} + \partial _y V \hat{y} + \partial _z V \hat{z}\big) $$
Is it right to say that along the ##z## axis,
$$E_z = - \partial _z V$$
and therefore the potential evaluated along the ##z## axis is as such,
$$V = - \int \ dz \ E_z$$

where I can pick the constant to be an arbitrary number?

Thanks in advance!

Homework Equations

The Attempt at a Solution

 
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Sure. Usually the potential is zero at infinity, but it doesn't have to be.
 
kuruman said:
Sure. Usually the potential is zero at infinity, but it doesn't have to be.

Thank you!
 
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