- #1
Boody
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Homework Statement
I know that the work done by an electrostatic force is given by :
W = Fdcosθ (scalar product)
W = qE d cosθ
and I know that the electric potential is V = -W/q ,
where the work here is the work done by the electrostatic force.
2. The attempt at a solution
I have found that the work done by the electrostatic force is positive ,whether it is attraction or repulsion ( of course when the displacement is with the direction of the force)
(to see that apply the work equation to a positive charge +q and negative charge -q)
with that result ( when electrostatic force acts alone , the work done is +ve whether attraction or repulsion) ,
we (or I ) see that V = -W/q is negative when q is positive and positive when q is negative
why is that ?
and , how to interpret that (V is -ve for +ve charge , V is +ve for -ve charge) ?
I am looking for a conceptual answer , I do not need so much mathematical explanation.
Thanks