Understanding Force Summation and Resultant Forces on a Slab

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The discussion revolves around calculating the resultant force on a slab, where the user has summed the forces to obtain a downward force of 1400 N, which aligns with the textbook. However, confusion arises as the textbook indicates the resultant force (Fr) as upward. Participants clarify that the schematic representation is general and not specific to the problem, suggesting the positive force notation indicates direction rather than an actual upward force. The user seeks to understand this discrepancy, particularly regarding the placement of the resultant force at point P(x,y). Overall, the conversation highlights the importance of interpreting force direction correctly in physics problems.
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Homework Statement


60f83f1915e83c016d92ecc2c7e13a1b.png


Find the magnitude and direction of a resultant force equivalent to the given force system and locate its point of application on the slab.

The Attempt at a Solution


So I summed the forces to get -1400 N, or a 1400 N force downward (the book agrees with that). Why is the resultant force going upward? It seems to me that they have printed a 1400 N force upward. I have no issue with the rest of the problem, but was hoping someone could explain to me why Fr is going upward.
 
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Permanence said:

Homework Statement


60f83f1915e83c016d92ecc2c7e13a1b.png


Find the magnitude and direction of a resultant force equivalent to the given force system and locate its point of application on the slab.

The Attempt at a Solution


So I summed the forces to get -1400 N, or a 1400 N force downward (the book agrees with that). Why is the resultant force going upward? It seems to me that they have printed a 1400 N force upward. I have no issue with the rest of the problem, but was hoping someone could explain to me why Fr is going upward.
It's just schematic and general. It's not meant to represent exactly the solution to this specific problem.

Chet
 
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Thank you for the response.
In the summary of the conclusion they say a Force of Fr = 1400 N is placed at P(x,y). So I assumed they wanted a positive force.
 
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