Understanding Fourier Transform: Solving Homework with Clear Steps

robertjford80
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Homework Statement



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The Attempt at a Solution



I don't understand this step. It's got to be some sort of identity that I missed. I also don't understand why the limits of integration change.
 
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Here's an easy way of seeing it:

Remember that the integral over an even interval of an odd function is zero
\int_{-L}^L f(x) dx = 0
if f(-x) = -f(x).

You can see fairly easily that \frac{\sin(\alpha)}{\alpha} is an even function and \sin(\alpha x) is an odd function; therefore \frac{\sin(\alpha) \sin(\alpha x)}{\alpha} is odd and it's integral vanishes over an even support interval.
 
ok, I understand what you mean, although it took me about 30 minutes to get it. I still understand why the limits of integration change. I also don't understand why 1/pi changes to 2/pi though I think it has something to with the change in the limits of integration.
 
For an even function f(-x) = f(x), you can show that \int_{-L}^L f(x) dx = 2 \int_0^L f(x) dx
 
cool
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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