- #1
Master J
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Is my proof of Kepler's 2nd law correct?
area of sector of circle/ellipse (that the planet sweeps out): (1/2)(r^2)O
O is theta!
dA/dO = (1/2) (r^2)
dA= (1/2) (r^2) dO
dA/dt = (1/2) (r^2) dO/dt
It can't be that simple? Can it??
area of sector of circle/ellipse (that the planet sweeps out): (1/2)(r^2)O
O is theta!
dA/dO = (1/2) (r^2)
dA= (1/2) (r^2) dO
dA/dt = (1/2) (r^2) dO/dt
It can't be that simple? Can it??