strangequark
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Ok, this is my last study problem, I think I got it, but my answers seem a little odd...
A rocket of length 1000 meters is at rest in S'. The nose of the rocket is atx'=0and the tail of the rocket is atx'=-1000 meters. S' is moving with a velocity of v=\frac{3c}{5} in the positive x direction relative to S.
Four events are given:
Event A is the synchronizing event where the nose of the rocket is at the origin in both frames:
x_{A}=x'_{A}=t_{A}=t'_{A}=0
Event B is simultaneous with A in S:
t_{B}=t_{A}=0
Event C is when the tail of the rocket passes the origin as observed in S
Event D is simultaneous with C and is when an observer in S sees the nose of the rocket pass by him.
x'=\gamma(x-vt)
t'=\gamma(t-\frac{vx}{c^{2}}
I also used,
L=\frac{L_{0}}{\gamma}
This is why I'm worried... it seems straight-forward...
All I did was calculate the length of the rocket as observed in S:
L=\frac{1000 meters}{5/4}=800 meters
I believe this gives me spatial coordinates for all of the events...
x_{C}=x_{A}=0
x_{B}=-800 meters
x_{D}=800 meters
as well as temporal coordinates:
t_{A}=t_{B}=0 (A is given in the problem and A,B are simultaneous)
t_{C}=t_{D}=\frac{x_{C}-x_{B}}{v}=\frac{x_{D}-x_{A}}{v}=4.4475 x 10^{-6} seconds
Then I just applied the coordinate transforms, and got:
x'_{A}=0 (given)
x'_{B}=-1000 meters
x'_{C}=-1000 meters
x'_{D}=0
t'_{A}=0
t'_{B}=2.0014 x 10^{-6} seconds
t'_{C}=5.5559 x 10^{-6} seconds
t'_{D}=3.55802 x 10^{-6} seconds
Now, everything here looks a little wierd... events B and C in the S' frame happen in the same place? And the sequence of events in S' is A-B-D-C?
Am I mis-applying the transforms or misinterpreting the problem?
If not, could someone please help me with interpreting the answers?
Much thanks in advance!
Homework Statement
A rocket of length 1000 meters is at rest in S'. The nose of the rocket is atx'=0and the tail of the rocket is atx'=-1000 meters. S' is moving with a velocity of v=\frac{3c}{5} in the positive x direction relative to S.
Four events are given:
Event A is the synchronizing event where the nose of the rocket is at the origin in both frames:
x_{A}=x'_{A}=t_{A}=t'_{A}=0
Event B is simultaneous with A in S:
t_{B}=t_{A}=0
Event C is when the tail of the rocket passes the origin as observed in S
Event D is simultaneous with C and is when an observer in S sees the nose of the rocket pass by him.
Homework Equations
x'=\gamma(x-vt)
t'=\gamma(t-\frac{vx}{c^{2}}
I also used,
L=\frac{L_{0}}{\gamma}
The Attempt at a Solution
This is why I'm worried... it seems straight-forward...
All I did was calculate the length of the rocket as observed in S:
L=\frac{1000 meters}{5/4}=800 meters
I believe this gives me spatial coordinates for all of the events...
x_{C}=x_{A}=0
x_{B}=-800 meters
x_{D}=800 meters
as well as temporal coordinates:
t_{A}=t_{B}=0 (A is given in the problem and A,B are simultaneous)
t_{C}=t_{D}=\frac{x_{C}-x_{B}}{v}=\frac{x_{D}-x_{A}}{v}=4.4475 x 10^{-6} seconds
Then I just applied the coordinate transforms, and got:
x'_{A}=0 (given)
x'_{B}=-1000 meters
x'_{C}=-1000 meters
x'_{D}=0
t'_{A}=0
t'_{B}=2.0014 x 10^{-6} seconds
t'_{C}=5.5559 x 10^{-6} seconds
t'_{D}=3.55802 x 10^{-6} seconds
Now, everything here looks a little wierd... events B and C in the S' frame happen in the same place? And the sequence of events in S' is A-B-D-C?
Am I mis-applying the transforms or misinterpreting the problem?
If not, could someone please help me with interpreting the answers?
Much thanks in advance!