Understanding OPD in Light Ray Equations

  • Thread starter kelvin macks
  • Start date
  • Tags
    Light Ray
In summary, the conversation discusses the confusion about the OPD (optical path difference) of ray 1 and ray 2 in a given equation. One person suggests that ray 2 goes through the film twice, while another clarifies that it is refracted at A and reflected at B. The conversation also touches on the computation of the effective path difference and the total physical distance traveled by ray 2.
  • #1
kelvin macks
60
0

Homework Statement



i don't understand why the OPD of ray 1 and ray 2 is as shown in the notes.i don't understand why the equation given is (nt +nt)-(0.5 lambda)... why is nt +nt ?

Homework Equations





The Attempt at a Solution

 

Attachments

  • DSC_0019.jpg
    DSC_0019.jpg
    55.4 KB · Views: 445
Physics news on Phys.org
  • #2
could it be that ray 2 goes through the film twice.
 
  • #3
Simon Bridge said:
could it be that ray 2 goes through the film twice.

do u mean the ray 1 has phase difference of -0.5lambda, whereas the light ray 2 undergo refelction twice so it should be 2nt. to find the relative difference between 1 AND 2 , just take 2nt -0.5lambda?
 
  • #4
do u mean the ray 1 has phase difference of -0.5lambda, whereas the light ray 2 undergo refelction twice so it should be 2nt. to find the relative difference between 1 AND 2 , just take 2nt -0.5lambda?
Here, let me help with that:
Do you mean the ray 1 has phase difference of -0.5lambda, whereas the light ray 2 undergo reflection twice so it should be 2nt? to find the relative difference between 1 AND 2 , just take 2nt -0.5lambda?​

Consider: why should anyone be bothered to answer your questions if you cannot be bothered to type out the two extra characters in the word "you" (etc)?

Note:
"-0.5##\small\lambda##" is not a phase difference.
ray 2 does not undergo reflection twice - it is refracted at A and reflected at B.
So the short answers to your two questions are: no, and, no.

The effective path difference is computed from the actual distance traveled, modified by the phase changes.
What is the total physical distance ray 2 travels from point A to point B?
 
  • #5


I can understand your confusion about the OPD (Optical Path Difference) in light ray equations. The equation given, (nt + nt) - (0.5 lambda), represents the total distance traveled by ray 1 and ray 2, which is equal to the OPD. The first part, (nt + nt), represents the distance traveled by the rays in the medium, while the second part, (0.5 lambda), represents the distance traveled in the air. This is because when light travels from one medium to another, it experiences a change in speed, which affects its wavelength and therefore its path.

To better understand this equation, it may be helpful to think of it in terms of phases. When two waves combine, their phases can either add constructively or destructively. In this case, the equation is representing the phase difference between the two rays, which is equal to the OPD.

I suggest reviewing the notes and any related concepts to gain a better understanding of the equation and how it relates to the OPD. Additionally, you can also try to visualize the path of the rays and how they interact with different mediums to gain a better understanding. I hope this helps clarify your confusion.
 

Related to Understanding OPD in Light Ray Equations

1. What is OPD in light ray equations?

OPD stands for Optical Path Difference, which is the difference in distance that a light ray travels between two points. In light ray equations, OPD is used to calculate the phase difference between two waves of light.

2. Why is OPD important in studying light rays?

OPD is important because it helps us understand how light behaves as it travels through different media and interacts with different surfaces. It is particularly useful in designing optical components such as lenses and mirrors.

3. How is OPD calculated in light ray equations?

OPD is calculated by taking the difference in distance traveled by a light ray between two points and dividing it by the wavelength of the light. This gives us the number of wavelengths that the light has traveled, which is used to determine the phase difference.

4. What factors can affect the OPD in light ray equations?

The main factors that can affect OPD are the refractive index of the medium that the light is passing through, the distance between the two points, and any changes in the shape or properties of the medium along the path of the light ray. These factors can cause the light ray to bend, reflect, or diffract, resulting in changes in the OPD.

5. How is OPD used in practical applications?

OPD is used in many practical applications, such as in the design of lenses for cameras and telescopes, in the measurement of surface roughness, and in interferometry, which is a technique used to measure small changes in distance. It is also important in understanding the principles of holography and other forms of optical imaging.

Similar threads

  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
2
Replies
39
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
918
  • Introductory Physics Homework Help
Replies
12
Views
109
  • Differential Equations
Replies
7
Views
401
  • Introductory Physics Homework Help
Replies
3
Views
96
  • Introductory Physics Homework Help
Replies
1
Views
813
  • Introductory Physics Homework Help
Replies
12
Views
2K
Replies
3
Views
1K
Back
Top