Understanding Optical Power in Simple Lens Equations

  • Thread starter Thread starter rambo5330
  • Start date Start date
  • Tags Tags
    Optics
AI Thread Summary
Optical power is defined as the reciprocal of the focal length (P = 1/f). In the given problem, with a focal length of 6.7 m-1, the optical power is indeed 6.7. Therefore, the equation 1/p + 1/q should equal the optical power, confirming that 1/p + 1/q = 6.7 is correct. This means the initial assumption about the equation is valid. Understanding these relationships is crucial for solving lens equations effectively.
rambo5330
Messages
83
Reaction score
0

Homework Statement


I am given a question with the focal length stated in optical power
i.e 6.7m-1

what is optical power it is stated that it is = to 1/f

so in the equation 1/p + 1/q = 1/f
is it right to assume that 1/p + 1/q = 6.7
or is it 1/6.7
??

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Yes, optical power is defined as 1/f for the lens.
Your first assumption is correct.
1/p + 1/q = power of lens
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top