Understanding Pressure Distribution in a Rotating Vessel of Water

glebovg
Messages
156
Reaction score
0
A closed vessel full of water is rotating with constant angular velocity \Omega about a horizontal axis. Show that the surfaces of equal pressure are circular cylinders whose common axis is at a height g/{\Omega}^2 above the axis of rotation.

Any ideas? I do not know how to start.
 
Physics news on Phys.org
Choose an arbitrarily located volume element of the water. Think about what forces act on the element. Then think about what law you can use to relate the forces to the motion.
 
TSny said:
Choose an arbitrarily located volume element of the water. Think about what forces act on the element. Then think about what law you can use to relate the forces to the motion.

You might as well just say: start answering the question. Your answer is the most general answer in fluid dynamics! :smile:
 
The trick, of course, is to transform the "general answer" into a specific answer.

Thus, you will need to identify the specific forces acting on a fluid element and relate the direction of one of those forces to the orientation of a surface of constant pressure. You will need to identify the specific magnitude and direction that the net force must have to produce the specific type of motion of the fluid element.

You have not indicated what aspects of the problem you understand and what aspects are giving you trouble, so it's a bit hard to know how to start helping you.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top